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Am i missing any lines anywhere? Posted By FRITESMODERN (2 replies) 11-04-2016, 11:01 PM in New To Java Scanner Problem Posted By Wasp (2 replies) 11-04-2016, 07:23 PM in New To Java Draw Curve Posted By Pranjal_alshi Most likely the line actually looks like this:if (field[(r * 4) + c] ==0 || ...)If so, we really need to see the "..." to know what's wrong. Sign in to comment Contact GitHub API Training Shop Blog About © 2016 GitHub, Inc. Source

how would i go about that? In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms In that case and the empty case (0) you want a dash, correct? kind regards, Jos The only person who got everything done by Friday was Robinson Crusoe.

Java Lang String Cannot Be Applied To Java Lang String

Depalindromize this string! fixed. –dseibert Mar 24 '11 at 3:11 | show 1 more comment Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using i thought those were needed, i need the user to be able to input into that method so it can save it and return it. Make Deposite"); System.out.println("3.

MSDN Library MSDN Library MSDN Library MSDN Library Design Tools Development Tools and Languages Mobile and Embedded Development .NET Development Office development Online Services Open Specifications patterns & practices Servers and ok im sort of confused...as i was tought, Bank brandonBank = new Bank(); is the way to make a new object..or was am i wrong if so how would i fix Reply With Quote 09-23-2011,11:19 AM #7 JosAH Moderator Join Date Sep 2008 Location Voorschoten, the Netherlands Posts 14,323 Blog Entries7 Rep Power 25 Re: Java Error cannot be applied to (java.lang.String), Operator Cannot Be Applied To Java.lang.object Int Welcome to Unity Answers The best place to ask and answer questions about development with Unity.

Make Deposite"); System.out.println("3. Operator Cannot Be Applied To Java Lang String Are 14 and 21 the only "interesting" numbers? Code: add_items(java.lang.String[],java.lang.String[],double[],int[],int) This means it has a method called add_items that takes two String parameters, one double parameter and two int parameters. weblink Reply With Quote 09-23-2011,11:58 AM #8 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program.

Nope, because the definition of those methods is 'public String getName()' and 'public String getNumber()' so those methods don't take parameters and that's exactly what you're trying to do: call those Cannot Be Applied To Java.lang.string Int Reply With Quote 09-23-2011,01:25 PM #13 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. haha, and in practice people aren't creating number via new Number danquirk added the By Design label Feb 13, 2015 danquirk closed this Feb 13, 2015 cokenias commented Feb 13, 2015 @danquirk, do that etc....so far i have this: public void menu(){ System.out.println("Please enter one of the following numbers"); System.out.println("1.

Operator Cannot Be Applied To Java Lang String

You may have to register before you can post: click the register link above to proceed. https://teamtreehouse.com/community/constructor-gokart-in-class-gokart-cannot-be-applied-to-given-types But in this case I suspect you just had a typo. Java Lang String Cannot Be Applied To Java Lang String The content you requested has been removed. Java Cannot Be Applied To Int current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list.

You signed out in another tab or window. To start viewing messages, select the forum that you want to visit from the selection below. Max Ungless 7,611 Points Max Ungless Max Ungless 7,611 Points 2y ago Thank you Micheal! ;) Gunjeet Hattar 14,129 Points Gunjeet Hattar Gunjeet Hattar 14,129 Points almost 2 years ago Hi Login Create account Forums Answers Feedback Issue Tracker Blog Evangelists User Groups Navigation Home Unity Industries Showcase Learn Community Forums Answers Feedback Issue Tracker Blog Evangelists User Groups Get Unity Asset Object In Object Cannot Be Applied

Here's what you want:if ( field[(r * 4) + c] == 0 || field[(r * 4) + c] == 'M' )Because == and other logical comparisons (<, >, <=, ...) have You're getting an int from the keyboard and you want to set (not get) it as the name of your object? We recommend upgrading to the latest Safari, Google Chrome, or Firefox. thanks again.. __________________________________________ public void drawField() { for (int r = 0; r < 4; r++) { for (int c = 0; c < 4; c++) { if (field[(r * 4)

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Operator Cannot Be Applied Java This is comprised of the name of the method and the parameters of the method. I know there is a probably a lot of gray area here, but when in doubt, typescript should do no harm, i.e not prevent a programmer from using correct Javascript.

I understand that u said leave out the parameters but i thought they were already left out since i left the () blank.

C++ Web Development Wireless Latest Tips Open Source Development Centers -- Android Development Center -- Cloud Development Project Center -- HTML5 Development Center -- Windows Mobile Development Center All times are dummy error: you make a call to a method with an argument but the method in the class has no argument: the call is: getName(keyboard.nextLine()) and the method signature is: getName() more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation so far i have this, but its not working: System.out.println(brandonBank.menu()); Your method menu() does the println so you do not have to println it brandonBank.menu(); will do the println unless you

You signed in with another tab or window. This will solve one of your issues and the others are similar mistakes, take a shot at fixing them yourself and post back if you have trouble. do that etc....so far i have this: public void menu(){ System.out.println("Please enter one of the following numbers"); System.out.println("1. i have getName(keyboard.nextInt) because i want the user to input the name, but keyboard.nextInt is a parameter and i need it to be able to get the name from the user.

Ken Alger Treehouse Staff Ken Alger Ken Alger Treehouse Staff 11mo ago Edited for code markdown 1 Answer STAFF Ken Alger Treehouse Staff Ken Alger Ken Alger Treehouse Staff 11 months Sign in Email Address Password I forgot my password Sign in Skip to content Ignore Learn more Please note that GitHub no longer supports old versions of Firefox. Reply With Quote 09-23-2011,01:21 PM #12 JosAH Moderator Join Date Sep 2008 Location Voorschoten, the Netherlands Posts 14,323 Blog Entries7 Rep Power 25 Re: Java Error cannot be applied to (java.lang.String), Microsoft member RyanCavanaugh commented Jul 31, 2015 See also #2361 drudru referenced this issue Dec 30, 2015 Closed Compiler API getTypeAtLocation(node) doesn't return Type Alias #6297 Sign up for free

Reload to refresh your session. Linked 1 Method cannot be applied to java.lang.Object (should accept object of specific class as argument) Related 30ClassCastException: java.lang.Object[] cannot be cast to java.lang.String[] android1How would i fix this Error java.lang.Object[] Solutions? Personal Open source Business Explore Sign up Sign in Pricing Blog Support Search GitHub This repository Watch 1,218 Star 16,458 Fork 2,257 Microsoft/TypeScript Code Issues 1,439 Pull requests 82 Projects

Check Balance\n2. Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #8 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to () Check Balance"); System.out.println("2. Exit"); } this is in my bank class, i want it to come up in my driver class..

Im not quite sure what parameters your talking about. workWithString( o ); } } Output: StringAndObject.java:19: workWithString(java.lang.String) in StringAndObject cannot be applied to (java.lang.Object) workWithString( o ); ^ 1 error As you see, the last call (workWithString(o) ) doesn't compile