Home > Cannot Be > Cannot Be Applied To Java.lang.object

Cannot Be Applied To Java.lang.object

Rob Spoor Sheriff Posts: 20717 68 I like... so you would do(im assuming), insert(mylist,25); its a program for my CSII class. Object [][] entryList = new Object[20][4]; public void displayResult() { String sqlQuery; sqlQuery = "SELECT * FROM History WHERE receiver_id = '" + this.receiverId.getText() + "'"; clientObj.sendSql(this.type1, this.type2, sqlQuery); try { Given the get(0) here: String result = Game.getStringFromGame(Game.getGames().get(0)); The return type of getGames() is probably a Collection of some sort. http://electrictricycle.net/cannot-be/cannot-be-applied-to-java-lang-object-int.html

String.valueOf( int i ) uses Integer.toString( int i ) The creaters of Java are big on putting code in one place and calling it when needed. Inheritance All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton FAQs Note that you could also create a new JDK SDK definition here, by clicking the "New" button, rather than where we did above.3) Set the "Project language level" as appropriate.4) Be Nathaniel Stodard
SCJP, SCJD, SCWCD, SCBCD, SCDJWS, ICAD, ICSD, ICED Joel McNary Bartender Posts: 1840 I like...

more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation asked 5 years ago viewed 15698 times active 5 years ago Linked 1 Method cannot be applied to java.lang.Object (should accept object of specific class as argument) Related 30ClassCastException: java.lang.Object[] cannot Second, you are trying to put a single Object into your entryList[i] position. Home JetBrains Support Submit a request Community Sign in JetBrains Support Community IntelliJ IDEA Users JRE classes like java.lang.String cannot be resolved.

Copyright 2006 - 2015, Java Programming Forum CodeDump Add Browse Sign up Sign in Select language ActionScript Ajax Android AngularJS Apache Configuration AppleScript ASP.NET (C#) AutoHotkey Bash Brainfuck C C# C++ Help would be appreciated! I would suggest Option 1. Why put a warning sticker over the warning on this product?

Source (Stackoverflow) http://stackoverflow.com/questions/35925176/method-cannot-be-applied-to-java-lang-object-should-accept-object-of-specific-c Comments Please enable JavaScript to view the comments powered by Disqus. × Email codedump link for Method cannot be applied to java.lang.Object (should accept object of specific class I have configured a SDK for the module project. Can a countable number of intersections of subsets or their complements be the null set? https://coderanch.com/t/401495/java/java/applied-int-Java-Lang-Object Add your answer Source Submit Cancel Report Abuse I think this question violates the Community Guidelines Chat or rant, adult content, spam, insulting other members,show more I think this question violates

The main method is included below, this works fine without GUI, but I need to add it to GUI. int i = 5; Integer j = new Integer(i); String s = j.toString(); <- use the toString method of the Integer object The Integer class has one more trick up its What's New? Mark Perfect World Programming, LLC - iOS Apps How to Ask Questions the Smart Way FAQ Rob Spoor Sheriff Posts: 20717 68 I like...

you said have the SDK "listed as a dependency for the module." I just want to make sure you do not mean it is listed in the list of dependencies on Posted By MS-POWER (2 replies) Yesterday, 07:58 PM in New To Java configure SSL sockets? You don't show your getGames definition, but the error message indicates you're returning an Object value from it. Depalindromize this string!

Extra string creation? this contact form It might be tempting to try int i = 5; String s = i.toString(); but "int" is a primitive type, not an object so that won't compile. Nathaniel Stoddard Ranch Hand Posts: 1258 posted 12 years ago Object yourObject = new Object[] {objectOne, objectTwo, objectThree, objectFour}; Or the long way Object yourObject = new Object[4]; yourObject[0] = objectOne; Nathaniel Stodard
SCJP, SCJD, SCWCD, SCBCD, SCDJWS, ICAD, ICSD, ICED Post Reply Bookmark Topic Watch Topic New Topic Similar Threads I don't get it..cannot resolve symbol.

Reload to refresh your session. Under the covers when you reference a class the JVM stores the information about that class in an object, and that's the object we're working on now. If you are at an office or shared network, you can ask the network administrator to run a scan across the network looking for misconfigured or infected devices. have a peek here Assuming that x is 1, what can be the result of the following Boolean expressions:?

Posted By JosAH (1 replies) Yesterday, 12:38 PM in Networking Can I develop this in java? Mike Gershman SCJP 1.4, SCWCD in process Post Reply Bookmark Topic Watch Topic New Topic Similar Threads conversions toString() behaviour? because that is where the problem is.

Can I get a dual entry Schengen visa for tourism purpose for me and my wife?

posted 10 years ago First of all, I'm assuming you're using Java 1.5, with all the autoboxing. To turn an integer (or similar number) into a String? My question is .. John Ciardi Rick Portugal Ranch Hand Posts: 243 posted 11 years ago Nicely said.

You want to store ints, so the Integer wrapper class would fit best: public static void insert(List l, int data) { for (int i = 0; i < l.size(); i++) { I am looking for referrals which is why I need YOU! New post © 2000— JetBrains s.r.o. http://electrictricycle.net/cannot-be/cannot-be-applied-to-int-java-lang-string.html fixed. –dseibert Mar 24 '11 at 3:11 | show 1 more comment Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using

Definitely going to post here with more questions in the future if I have them! Operator * cannot be applied to java.lang.String,int? You can only upload files of type PNG, JPG, or JPEG. Reload to refresh your session.

System.out.print("Enter list of numbers\n"); while (sn.hasNextInt()) { number = sn.nextInt(); list.add(new Integer(number)); } Is how the numbers are added to the ArrayList.