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Cannot Be Applied To Java.lang.string Error


The remedy is simple: leave out the parameters and the compiler will be happy. Leveling Pokemon using the Lumiose Tower infinite loop path On verses, from major Hindu texts, similar in purport with the verses and messages found in the Bhagawat Gita Making a large Book Review: Murach's Java Servlets and JSP Phobos - A JavaFX Games Engine: Part 2 - JavaFX Scene API and the FSM Maven Tutorial 2 - Adding Dependencies Maven Tutorial 1 I'm currently working on making a simple 2D "engine" of sorts in which I can assign certain objects to certain coordinates and it will render them out there. http://electrictricycle.net/cannot-be/cannot-be-applied-to-int-java-lang-string.html

Browse other questions tagged java string user-interface java.lang.class or ask your own question. Why am i getting this errors while compiling my binary to hex converter.. There were about 33 errors that I fixed, though I get a message … Recommended Articles Nested array printing etc - designing for reuse Last Post 18 Minutes Ago This is Hot Network Questions Can I switch from past tense to present tense in an epilogue?

Java Lang String Cannot Be Applied To Java Lang String

Sorry, im really not that bad with this stuff but this has been puzzling me and even my professor couldn't help(or didn't want to) idk. do this 2. VBulletin, Copyright 2000 - 2016, Jelsoft Enterprises Ltd.

If not, let us know what you're actually trying to do with the line: entryList[i] = ... Check Balance"); System.out.println("2. To start viewing messages, select the forum that you want to visit from the selection below. Object In Object Cannot Be Applied Is it unethical to poorly translate an exam from Dutch to English and then present it to the English speaking students?

This code sample reproduces exactly your compilation error: class StringAndObject { public void workWithString( String s ) {} // We just care about public void workWithObject( Object o ) {} // Operator Cannot Be Applied To Java Lang String posted 10 years ago Hi, Welcome to JavaRanch! Thanks a lot for your help. Reply With Quote Quick Navigation Java Top Site Areas Settings Private Messages Subscriptions Who's Online Search Forums Forums Home Forums DevX Developer Forums .NET ASP.NET VB Classic Java C++ XML Web

Again thanks. Cannot Be Applied To Java.lang.string Int Read up on Comparable if you're not familiar with it, then use that to do your comparison. Reload to refresh your session. Is adding the ‘tbl’ prefix to table names really a problem?

Operator Cannot Be Applied To Java Lang String

I am new to Java can someone point me in the right direction? When you call a method you have to put the right number of parameters into the parentheses, and they have to be in the right order. Java Lang String Cannot Be Applied To Java Lang String If the user enters a String that isn't a valid number, those parseXXX methods will "throw an exception." Have you learned about those yet? [Jess in Action][AskingGoodQuestions] matt jamison Greenhorn || Java Cannot Be Applied To Int I am not a FORTRAN master; maybe somebody here is more familiar ...

It's mainly to be about 2D animation and the like, but that's besides the point. http://electrictricycle.net/cannot-be/cannot-be-applied-to-java-lang-string-java-lang-string.html posted 10 years ago After you get a String from the user, then the next thing you do is convert it to a double. DavidB 44 493 posts since Jul 2006 Community Member How To Create A 2D Coordinate Grid In Python Last Post 20 Hours Ago Hey everybody. Advisor professor asks for my dissertation research source-code How can I declare independence from the United States and start my own micro nation? Operator Cannot Be Applied To Java.lang.object Int

And you wouldn't want to do that here, since you want to convert from binary to hex. –Lone nebula Sep 28 '14 at 19:11 add a comment| 2 Answers 2 active I don't like the idea of silently accepting null however. –Mark Peters Mar 23 '11 at 20:16 Your code is missing the other third of the conditional expression. –Paŭlo How to harness Jupiter's gravitational energy? have a peek here Second, you are trying to put a single Object into your entryList[i] position.

javascript: x() beerchug matt jamison Greenhorn Posts: 7 posted 10 years ago just when i thought i was done. Operator Cannot Be Applied Java Reply With Quote 09-23-2011,10:07 AM #2 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. thanks.

idk what i was thinking, my professor taught me different so i was very confused, thanks for all your help.

Register Help Remember Me? The other thing is that you're still showing that admirable creativity in arranging logical operators. The same goes for &&; you have to write if (x equals a and x equals b) rather than if (x equals a and b) So putting this altogether, what you've either you correct the method call or the signature.

Join them; it only takes a minute: Sign up Java.lang.long cannot be applied to java.lang.string? asked 2 years ago viewed 1491 times active 2 years ago Related 2(java.lang.String) cannot be applied to (java.lang.Object)3SharedPreferences getLong() -> java.lang.String cannot be cast to java.lang.Long. I do not understand how one of the variables returned by a sub-routine can ever take a particular value. Check This Out Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #9 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to ()

The Errors i recieve are: E:\Lab 2\PhoneBookList.java:20: getName() in PhoneBook cannot be applied to (java.lang.String) entry.getName(keyboard.nextLine()); ^ E:\Lab 2\PhoneBookList.java:22: getNumber() in PhoneBook cannot be applied to (java.lang.String) entry.getNumber(keyboard.nextLine()); ^ Any help? Code Java: public class PayrollTest { public static void main(String[] args) { double number; // hold a number String input; // hold user input String str; // hold employee name if ((sideOne equals(sideTwo)) && (sideOne equals(sideThree))) { JOptionPane.showMessageDialog(null, "The Triangle is Equilateral"); break; } else if ((sideOne equals(sideTwo)) || (sideOne equals (sideThree))) { JOptionPane.showMessageDialog(null, "The Triangle is Isosceles"); break; } else If so, can you cast it? –justkt Mar 23 '11 at 19:48 add a comment| 3 Answers 3 active oldest votes up vote 1 down vote accepted That's because JComboBox.html.getSelectedItem() returns

Originally Posted by iceyferrara okay so by leaving out the parameters u mean take away the ()? Reply With Quote 09-23-2011,12:56 PM #10 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. String is a class, a String is an object, they can't be compared in this way. how would i get it there...

Reply With Quote 09-23-2011,01:25 PM #13 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. haha, For a better animation of the solution from NDSolve more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #7 Jayman Student of Life Reputation: 421 Posts: 9,532 Joined: 26-December 05 Re: Error: cannot be applied to

n-dimensional circles! Anyway, i am writing a program to tell what type of triangle the length of 3 sides make.