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Cannot Be Applied To Java.lang.string Java.lang.string

You want the compareTo() method. Is it just looking in the parent dictionary? First, you can't create a new Object with those parameters, because the Object constructor takes no parameters. This post has been edited by GregBrannon: 10 August 2011 - 10:22 PM Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #3 NappyxD New D.I.C Head Source

Hey, Thanx for your suggestion. Can any one tell me what that error is and how to fix it? posted 10 years ago You sure you put all those dots in? [Jess in Action][AskingGoodQuestions] matt jamison Greenhorn Posts: 7 posted 10 years ago whoops. Was there no tax before 1913 in the United States?

if ((sideOne + sideTwo < sideThree) || (sideTwo + sideThree < sideOne) || (sideOne + sideThree < side Two)) { JOptionPane.showMessageDialog(null, "Not a Triangle"); } else if ((sideOne.equals(sideTwo)) && (sideOne.equals(sideThree))) { public void run() { String s = ""; // s declared as String Object o = s; // o declared as Object // works because a String is also an Object When you call the equals() method, or any method, you use the "dot" operator (.) to link the object to the method -- i.e., a.equals(b) That's one thing. How can I avoid being chastised for a project I inherited which was already buggy, but I was told to add features instead of fixing it?

What I am trying to do is take value to combobox which is String array, and place that string into topic (where the (t) is now import java.util.Hashtable; import javax.jms.JMSException; import If you'd like to look at all the classes and the compiler download it Here. thanks. Last edited by iceyferrara; 09-23-2011 at 10:09 AM.

Reputation: 10042 Posts: 17,061 Joined: 19-March 11 Re: I get the error "operator - cannot be applied to java.lang.String, Posted 23 April 2012 - 10:00 PM Just to be clear: the I have it all working now. Jairaj Jan 30 at 13:00 Isn't your value variable a String? –TeChNo_DeViL Jan 30 at 13:07 You are trying to execute math on strings!! –Rotwang Jan 30 If I receive written permission to use content from a paper without citing, is it plagiarism?

I have a few more problems however. In the new Policy, bonus is based on the fact that one is … Exception in thread "main" java.lang.NoSuchMethodError: main 2 replies i am a first year student and i dont kind regards, Jos The only person who got everything done by Friday was Robinson Crusoe. Therefore, your Ex4 class is a subclass of the Object class, and your statement: super( "Orchard Game", pw, ph, 33333333 ); is calling a constructor of the Object class that doesn't

You can now find them here. I changed one method signature and broke 25,000 other classes. Reply With Quote 09-23-2011,11:58 AM #8 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. Free Video Tutorials for Java and Eclipse Beginners Reply With Quote 09-23-2011,10:49 AM #5 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied

more hot questions lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Science Other this contact form This code sample reproduces exactly your compilation error: class StringAndObject { public void workWithString( String s ) {} // We just care about public void workWithObject( Object o ) {} // You're getting an int from the keyboard and you want to set (not get) it as the name of your object? Articles Forum New Posts FAQ Calendar Forum Actions Mark Forums Read Quick Links Today's Posts Blogs Advanced Search Forum Java Programming New To Java Java Error cannot be applied to (java.lang.String),

Join them; it only takes a minute: Sign up Operator || cannot be applied to java.lang.string [closed] up vote -4 down vote favorite I am trying to impose || operator on This should help you get started, also do not forget your going to need a Scanner for user input. Are “Referendum” and “Plebiscite” the same in the meaning, or different in the meaning and nuance? have a peek here Today's Topics Dream.In.Code > Programming Help > Java I get the error "operator - cannot be applied to java.lang.String, Page 1 of 1 New Topic/Question Reply 4 Replies - 2964 Views

Is it unethical to poorly translate an exam from Dutch to English and then present it to the English speaking students? The other thing is that you're still showing that admirable creativity in arranging logical operators. Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #5 GregBrannon D.I.C Lover Reputation: 2250 Posts: 5,340 Joined: 10-September 10 Re: Object() in java.lang.Object cannot be applied

Today's Topics Dream.In.Code > Programming Help > Java Object() in java.lang.Object cannot be applied to (java.l Page 1 of 1 New Topic/Question Reply 4 Replies - 4406 Views - Last Post:

Buy you've defined entryList as a 2D array, so entryList[i] really should be an array of objects. here is my code /* Determines type of triangle based on length of sides. */ import javax.swing.JOptionPane; public class Triangles { public static void main(String[] args) { //get the length of Reference Sheets Code Snippets C Snippets C++ Snippets Java Snippets Visual Basic Snippets C# Snippets VB.NET Snippets ASP.NET Snippets PHP Snippets Python Snippets Ruby Snippets ColdFusion Snippets SQL Snippets Assembly Snippets dummy error: you make a call to a method with an argument but the method in the class has no argument: the call is: getName(keyboard.nextLine()) and the method signature is: getName()

It turns out the compiler only knows that o was declared as Object but it doesn't have a way to know if that object is a string or is something else You can call toString() on its result to return the string representation of your object. So given that sideOne and sideTwo are Strings, instead of if (sideOne == sideTwo) you must instead write if (sideOne.equals(sideTwo)) The second thing is that, in Java, to say if (x http://electrictricycle.net/cannot-be/cannot-be-applied-to-int-java-lang-string.html Solutions?

Is it just looking in the parent dictionary? Ernest Friedman-Hill author and iconoclast Marshal Posts: 24212 35 I like... Join them; it only takes a minute: Sign up How to solve “operator * cannot be applied to java.lang.string”? i keep getting this error:Exception in thread "main" java.lang.NoSuchMethodError: main … Exception in thread "main" java.lang.NullPointerException 2 replies The Vehicle.java is the file that I am modifying.

If the user enters a String that isn't a valid number, those parseXXX methods will "throw an exception." Have you learned about those yet? [Jess in Action][AskingGoodQuestions] matt jamison Greenhorn Does sputtering butter mean that water is present? item.productPrice = (TextView) convertView .findViewById(R.id.textViewTotal); value = String.format("%.2f", curProduct.price); if (mShowPrice) { item.productPrice.setText("Total Price: " + String.valueOf(curProduct.price * ShoppingCartActivity.getProductQuantity(curProduct))); } else{ item.productPrice.setText("RM" + String.valueOf(value)); } java android share|improve this question edited thanks for all the help im trying to figure it out ill give an update in a little.

Reply With Quote 09-23-2011,10:10 AM #4 j2me64 Senior Member Join Date Sep 2009 Location Zurich, Switzerland Posts 962 Rep Power 8 Re: Java Error cannot be applied to (java.lang.String), phone book Reply With Quote 09-23-2011,10:07 AM #2 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. either you correct the method call or the signature. Thanks a lot for your help.

okay so by leaving out the parameters u mean take away the ()? I understand that u said leave out the parameters but i thought they were already left out since i left the () blank. You can't, unfortunately, write a.equals(!b) to mean "a not equal to b". posted 10 years ago What you need to do is convert the Strings to numbers (probably type "int" if you don't need fractional lengths, or "double" if you do.) To convert

Originally Posted by iceyferrara okay so by leaving out the parameters u mean take away the ()? i thought those were needed, i need the user to be able to input into that method so it can save it and return it. And it works. It's mainly to be about 2D animation and the like, but that's besides the point.

How can tilting a N64 cartridge cause such subtle glitches? Why put a warning sticker over the warning on this product? Forum Program Your Site General Web Development & Application Design Issues cannot be applied to (java.lang.String) The SitePoint Forums have moved. I have used the method value = String.format("%.2f", curProduct.price); and it works, but when i want to apply value * ShoppingCartActivity.getProductQuantity(curProduct), it says that operator * cannot applied to java.lang.string.