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Cannot Be Applied To Product Type


So you can't compare a string with a datetime. This is my pillow iptables not dropping by IP and port? Optional Password I have read and agree to the Terms of Service and Privacy Policy Please subscribe me to the CodeProject newsletters Submit your solution! FULL RISK DISCLOSURE: Futures, foreign currency and options trading contains substantial risk and is not for every investor. have a peek here

Thread Tools Display Modes 06-12-2014, 07:07 AM #1 nikolaalx Senior Member Join Date: Mar 2014 Posts: 165 Thanks: 0 Thanked 4 times in 3 posts Operator && cannot be Advisor professor asks for my dissertation research source-code Why is this C++ code faster than my hand-written assembly for testing the Collatz conjecture? Storage of a material that passes through non-living matter Heroku Gives me Error like "Push rejected, Unauthorized access." If I receive written permission to use content from a paper without citing, Sign in using Search within: Articles Quick Answers Messages Use my saved content filters home articles Chapters and Sections> Search Latest Articles Latest Tips/Tricks Top Articles Beginner Articles Technical Blogs Posting/Update http://stackoverflow.com/questions/16595781/operator-cannot-be-applied-to-operands-of-type-string-and-int

Operator Cannot Be Applied To Types String And Number Typescript

That being said I would convert a.callDate to a DateTime. Thanks for reporting these, Marcin! If you build it you should see the error in `BugExtension.swift`, line 15. if (!(Session["counter"])) { counter = (int)Session["counter"]; } Posted 24-Jul-12 6:33am kellycx745 Add a Solution 3 solutions Top Rated Most Recent Rate this: Please Sign up or sign in to vote.

var detail = from a in db.Details where (Convert.ToDateTime(a.callDate) >= StartDateTime && Convert.ToDateTime(a.callDate) <= EndDateTime) select a; share|improve this answer answered Jan 28 at 13:58 Gilgamesh 576113 add a comment| up private int priorSessionTrades = 0; // This varialbe holds the number of trades taken prior to each session break. View all posts by dotnetcoderoom This entry was posted on Monday, September 8th, 2008 at 5:48 pm and tagged with C#, Datatype Handling and posted in C#. Typescript Number Solution 6 Accept Solution Reject Solution Hello, Please try below corrected one : string[] result=new string [4]; string accessnumber = null; accessnumber = ""; result = clsObj.FnCheckAccessNo(); if ( Convert.ToString(result[0]) == Convert.ToString(1)) {

private int lastTrades = 2; private int startHours = 16; private int startMinutes = 40; private int endHours = 22; private int endMinutes = 55; Facebook Twitter YouTube nikolaalx View more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Solution 2 Accept Solution Reject Solution There is not much to add since the error message allready says it all... click for more info I realise that by now there are plenty of answers already but what exactly is your question? –Ciara Jan 28 at 14:04 add a comment| 4 Answers 4 active oldest votes

How did early mathematicians make it without Set theory? Typescript Parse Number It will be checked every OnBarUpdate() to determine when a trade has closed. Resolved SR-3049 Invalid use of "binary operator '&' cannot be applied to two 'Int' operands" Resolved relates to SR-1255 Binary operator '||' cannot be applied to two 'Bool' operands. I have attached screenshots of the errors.

Operator Cannot Be Applied To Types Number And Number

Hide Permalink Alex Johnson added a comment - 9 May 2016 11:49 AM Here is another case where this message makes it difficult to decipher the underlying mistake (I ran into The author specifically say that Type is string. –Adrian Godong May 16 '13 at 19:30 which means that the error is comparing sl.Type to his local Type variable. Operator Cannot Be Applied To Types String And Number Typescript Developers who offer products or other trading software tools to be used with the NinjaTrader trading platform are independent persons or companies that are in no manner affiliated with NT or Typescript Operator Cannot Be Applied To Types share|improve this answer answered May 16 '13 at 19:28 Nevyn 1,92311026 He stated that Type was a string.

products[] a = new products[productscopy.Count]; int type = int.Parse(textBox2.Text); int year = int.Parse(textBox1.Text); int br = 0; foreach (products sl in productscopy) { if (sl.Year == year && sl.Type == type) navigate here Your Email Password Forgot your password? How can I declare independence from the United States and start my own micro nation? For example, you may want to build a particular in-memory representation which isn’t really amenable to the provider’s model. Add Two Numbers In Typescript

share|improve this answer answered Jan 28 at 13:58 Simon Karlsson 2,906627 add a comment| up vote 0 down vote What does your schema look like? Because we are trying to add a string variable in a numeric variable. but not if (a == word) ... Check This Out Find More Posts by NinjaTrader_CalH « Previous Thread | Next Thread » Thread Tools Show Printable Version Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Posting Rules

Skilled in a variety of software languages, tools, and methodologies, with a special expertise in Microsoft .NET technologies. Operator Cannot Be Applied To Operands Of Type Is there a wage gap between smokers and non-smokers? var cartItems = from product in tsContainer.TS_Products where product.ProductId == TSObjects.GetProductIds(); where GetProductIds() method is below private const string PRODUCTID_ARRAY = "ProductID_Array"; public static void AddProductId(int productId) {

Browse other questions tagged c# linq datetime asp.net-web-api2 or ask your own question.

You can follow any responses to this entry through the RSS 2.0 feed. « Send e-mail in ASp.Net 2.0 and onwards inC# What is RSSfeed » 6 responses to “Operator + The DateTime.ParseExact cannot be translated properly in a database method. This is my pillow more hot questions question feed lang-cs about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Typescript Operators The NinjaTrader Support Forum is hosted and operated by NinjaTrader LLC (“NT”), a software development company which owns and supports the NinjaTrader trading platform.

You might change it to: if ( Session["counter"] != 0) { //... } Permalink Posted 24-Jul-12 6:42am CPallini391.7K Comments kellycx 24-Jul-12 12:54pm I changed the codes to My manager said I spend too much time on Stack Exchange. Do you need your password? this contact form He's using int.parse on a textbox for the type when he probably should just be using the string. –J...

May 16 '13 at 19:29 Why not sl.Type == textBox2.Text (instead of int.Parse(textBox2.Text))? I updated my question to show it. NinjaTrader Customer Service Use Kinetick, NinjaTrader’s preferred market data service - Learn More Free online training events - View Schedule Facebook Twitter YouTube The following user says thank you to it is not allowed.try the below tsContainer.TS_Products.where(product => TSObjects.GetProductIds().Contains(product.ProductId)) -------------------------------------------------------- Surender Singh Bhadauria My Blog Tuesday, January 10, 2012 6:42 AM Reply | Quote 0 Sign in to vote

When implementing your answer detail has an error that it cant convert IEnumerable to IQueryable –Mr.Smithyyy Jan 28 at 14:18 Not a problem at all. You are missing 'select' at the end of query.Please mark this post as answer if it solved your problem. Hide Permalink Mark Lacey added a comment - 28 Jul 2016 7:23 PM Assigning to Chris since he has a related bug for this. Of course when you execute the comparison the compiler doesn't like at all –Steve May 16 '13 at 19:31 add a comment| 3 Answers 3 active oldest votes up vote 2

How can I trust that this is google? is callDate a string? hence you cannot apply it to integer variables. As C# uses doesn't supports implicit typecasting, for string concatenation use "&" sign.